ack/lang/cem/cemcom.ansi/l_ev_ord.c

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/*
* (c) copyright 1987 by the Vrije Universiteit, Amsterdam, The Netherlands.
* See the copyright notice in the ACK home directory, in the file "Copyright".
*/
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/* $Id$ */
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/* Lint evaluation order checking */
#include "parameters.h"
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#ifdef LINT
#include <alloc.h> /* for st_free */
#include "interface.h"
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#ifdef ANSI
#include <flt_arith.h>
#endif /* ANSI */
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#include "arith.h" /* definition arith */
#include "label.h" /* definition label */
#include "expr.h"
#include "def.h"
#include "code.h" /* RVAL etc */
#include "LLlex.h"
#include "Lpars.h"
#include "stack.h"
#include "type.h"
#include "level.h"
#include "l_lint.h"
#include "l_state.h"
extern char *symbol2str();
PRIVATE check_ev_order();
check_and_merge(expr, espp, esp)
struct expr *expr;
struct expr_state **espp, *esp;
{
/* Checks for undefined evaluation orders in case of a non-sequencing operator.
* In addition the sets of used and set variables of both expressions are
* united.
* *espp will be pointing to this new list. esp is used for this list.
*/
register struct expr_state **pp, *p1, *p2;
int oper = expr->OP_OPER;
int is_sequencer =
(oper == '?' || oper == OR || oper == AND || oper ==',');
for (p1 = *espp; p1; p1 = p1->next) {
/* scan the list esp for the same variable */
p2 = esp;
pp = &esp;
while (p2) {
if ( /* p1 and p2 refer to the same location */
p1->es_idf == p2->es_idf
&& p1->es_offset == p2->es_offset
) {
/* check */
if (!is_sequencer)
check_ev_order(p1, p2, expr);
/* merge the info */
p1->es_used |= p2->es_used;
p1->es_referred |= p2->es_referred;
p1->es_set |= p2->es_set;
/* and remove the entry from esp */
*pp = p2->next;
free_expr_state(p2);
p2 = *pp;
}
else {
/* skip over the entry in esp */
pp = &p2->next;
p2 = p2->next;
}
}
}
/* If there is anything left in the list esp, this is put in
front of the list *espp is now pointing to, and *espp will be
left pointing to this new list.
*/
if (!esp)
return;
p1 = *espp;
*espp = esp;
while (esp->next)
esp = esp->next;
esp->next = p1;
}
PRIVATE
check_ev_order(esp1, esp2, expr)
struct expr_state *esp1, *esp2;
struct expr *expr;
{
if ( (esp1->es_used && esp2->es_set)
|| (esp1->es_set && esp2->es_used)
|| (esp1->es_set && esp2->es_set)
) {
expr_warning(expr,
"result of %s depends on evaluation order on %s",
symbol2str(expr->OP_OPER),
esp1->es_idf->id_text);
}
}
#endif /* LINT */