1994-06-24 11:31:16 +00:00
|
|
|
/* $Id$ */
|
1987-03-09 19:15:41 +00:00
|
|
|
/*
|
|
|
|
* (c) copyright 1987 by the Vrije Universiteit, Amsterdam, The Netherlands.
|
|
|
|
* See the copyright notice in the ACK home directory, in the file "Copyright".
|
|
|
|
*/
|
1984-11-26 15:04:22 +00:00
|
|
|
/* C R O S S J U M P I N G
|
|
|
|
*
|
|
|
|
* CJ.H
|
|
|
|
*
|
|
|
|
*/
|
|
|
|
|
|
|
|
#include <stdio.h>
|
1991-03-05 12:16:17 +00:00
|
|
|
#include <em_mnem.h>
|
|
|
|
#include <em_spec.h>
|
1984-11-26 15:04:22 +00:00
|
|
|
#include "../share/types.h"
|
|
|
|
#include "../share/debug.h"
|
|
|
|
#include "../share/global.h"
|
|
|
|
#include "../share/files.h"
|
|
|
|
#include "../share/get.h"
|
|
|
|
#include "../share/put.h"
|
|
|
|
#include "../share/lset.h"
|
|
|
|
#include "../share/map.h"
|
|
|
|
#include "../share/alloc.h"
|
|
|
|
#include "../share/aux.h"
|
|
|
|
#include "../share/def.h"
|
|
|
|
#include "../share/stack_chg.h"
|
|
|
|
#include "../share/go.h"
|
|
|
|
|
|
|
|
|
|
|
|
/* Cross jumping performs optimzations like:
|
|
|
|
*
|
|
|
|
* if cond then goto L1; if cond then goto L1
|
|
|
|
* S1; -----> S1;
|
|
|
|
* S2; goto L3;
|
|
|
|
* goto L2; L1:
|
|
|
|
* L1: S3;
|
|
|
|
* S3; L3:
|
|
|
|
* S2; S2;
|
|
|
|
* L2:
|
|
|
|
*
|
|
|
|
* CJ looks for two basic blocks b1 and b2 with the following properties:
|
|
|
|
* - there exists a basic block S such that SUCC(b1) = SUCC(b2) = {S}
|
|
|
|
* (so both have only 1 successor)
|
|
|
|
* - the last N (N > 0) instructions of b1 and b2, not counting a possible
|
|
|
|
* BRAnch instruction, are the same.
|
|
|
|
* As a result of the first condition, at least of the two blocks must end
|
|
|
|
* on an (unconditional) BRAnch instruction. If both end on a BRA, one block
|
|
|
|
* is chosen at random. Assume this block is b1. A new label L is put just
|
|
|
|
* before the N common instructions of block b2 (so this block is split
|
|
|
|
* into two). The BRA of b1 is changed into a BRA L. So dynamically the same
|
|
|
|
* instructions are executed in a slightly different order; yet the size of
|
|
|
|
* the code has become smaller.
|
|
|
|
*/
|
|
|
|
|
|
|
|
|
|
|
|
STATIC int Scj; /* number of optimizations found */
|
|
|
|
|
1991-10-25 14:27:59 +00:00
|
|
|
STATIC showinstr();
|
|
|
|
|
1984-11-26 15:04:22 +00:00
|
|
|
|
|
|
|
|
|
|
|
#define DLINK(l1,l2) l1->l_next=l2; l2->l_prev=l1
|
|
|
|
|
|
|
|
|
|
|
|
STATIC bool same_instr(l1,l2)
|
|
|
|
line_p l1,l2;
|
|
|
|
{
|
|
|
|
/* See if l1 and l2 are the same instruction */
|
|
|
|
|
|
|
|
if (l1 == 0 || l2 == 0 || TYPE(l1) != TYPE(l2)) return FALSE;
|
|
|
|
if (INSTR(l1) != INSTR(l2)) return FALSE;
|
|
|
|
switch(TYPE(l1)) {
|
|
|
|
case OPSHORT: return SHORT(l1) == SHORT(l2);
|
|
|
|
case OPOFFSET: return OFFSET(l1) == OFFSET(l2);
|
|
|
|
case OPPROC: return PROC(l1) == PROC(l2);
|
|
|
|
case OPOBJECT: return OBJ(l1) == OBJ(l2);
|
|
|
|
case OPINSTRLAB: return INSTRLAB(l1) == INSTRLAB(l2);
|
|
|
|
case OPNO: return TRUE;
|
|
|
|
default: return FALSE;
|
|
|
|
}
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
STATIC line_p last_mnem(b)
|
|
|
|
bblock_p b;
|
|
|
|
{
|
|
|
|
/* Determine the last line of a list */
|
|
|
|
|
|
|
|
register line_p l;
|
|
|
|
|
|
|
|
for (l = b->b_start; l->l_next != (line_p) 0; l = l->l_next);
|
1985-01-23 16:13:57 +00:00
|
|
|
while (l != (line_p) 0 && (INSTR(l) < sp_fmnem || INSTR(l) > sp_lmnem)) {
|
|
|
|
l = PREV(l);
|
|
|
|
}
|
1984-11-26 15:04:22 +00:00
|
|
|
return l;
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
STATIC bool is_desirable(text)
|
|
|
|
line_p text;
|
|
|
|
{
|
|
|
|
/* We avoid to generate a BRAnch in the middle of some expression,
|
|
|
|
* as the code generator will write the contents of the fakestack
|
|
|
|
* to the real stack if it encounters a BRA. We do not avoid to
|
|
|
|
* split the parameter-pushing code of a subroutine call into two,
|
|
|
|
* as the parameters are pushed on the real stack anyway.
|
|
|
|
* So e.g. "LOL a ; LOL b; ADI" will not be split, but
|
|
|
|
* "LOL a; LOL b; CAL f" may be split.
|
|
|
|
*/
|
|
|
|
|
|
|
|
line_p l;
|
|
|
|
bool ok;
|
|
|
|
int stack_diff,pop,push;
|
|
|
|
|
|
|
|
stack_diff = 0;
|
|
|
|
for (l = text; l != (line_p) 0; l = l->l_next) {
|
|
|
|
switch(INSTR(l)) {
|
|
|
|
case op_cal:
|
|
|
|
case op_asp:
|
|
|
|
case op_bra:
|
|
|
|
return TRUE;
|
|
|
|
}
|
|
|
|
line_change(l,&ok,&pop,&push);
|
|
|
|
/* printf("instr %d, pop %d, push %d, ok %d\n",INSTR(l),pop,push,ok); */
|
|
|
|
if (!ok || (stack_diff -= pop) < 0) {
|
|
|
|
return FALSE;
|
|
|
|
} else {
|
|
|
|
stack_diff += push;
|
|
|
|
}
|
|
|
|
}
|
|
|
|
return TRUE;
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
STATIC cp_loops(b1,b2)
|
|
|
|
bblock_p b1,b2;
|
|
|
|
{
|
|
|
|
/* Copy the loopset of b2 to b1 */
|
|
|
|
|
|
|
|
Lindex i;
|
|
|
|
loop_p lp;
|
|
|
|
for (i = Lfirst(b2->b_loops); i != (Lindex) 0;
|
|
|
|
i = Lnext(i,b2->b_loops)) {
|
|
|
|
lp = (loop_p) Lelem(i);
|
|
|
|
Ladd(lp,&b1->b_loops);
|
|
|
|
}
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
STATIC jump_cross(l1,l2,b1,b2)
|
|
|
|
line_p l1,l2;
|
|
|
|
bblock_p b1,b2;
|
|
|
|
{
|
|
|
|
/* A cross-jump from block b2 to block b1 is found; the code in
|
|
|
|
* block b2 from line l2 up to the BRAnch is removed; block b1 is
|
|
|
|
* split into two; the second part consists of a new label
|
|
|
|
* followed by the code from l1 till the end of the block.
|
|
|
|
*/
|
|
|
|
|
|
|
|
line_p l;
|
|
|
|
bblock_p b;
|
|
|
|
bblock_p s;
|
|
|
|
|
|
|
|
/* First adjust the control flow graph */
|
|
|
|
b = freshblock(); /* create a new basic block */
|
|
|
|
b->b_succ = b1->b_succ;
|
|
|
|
/* SUCC(b1) = {b} */
|
|
|
|
b1->b_succ = Lempty_set(); Ladd(b,&b1->b_succ);
|
|
|
|
/* SUCC(b2) = {b} */
|
|
|
|
Ldeleteset(b2->b_succ); b2->b_succ = Lempty_set(); Ladd(b,&b2->b_succ);
|
|
|
|
/* PRED(b) = {b1,b2} */
|
|
|
|
b->b_pred = Lempty_set(); Ladd(b1,&b->b_pred); Ladd(b2,&b->b_pred);
|
|
|
|
/* PRED(SUCC(b)) := PRED(SUCC(b)) - {b1,b2} + {b} */
|
|
|
|
assert(Lnrelems(b->b_succ) == 1);
|
|
|
|
s = (bblock_p) Lelem(Lfirst(b->b_succ));
|
|
|
|
Lremove(b1,&s->b_pred); Lremove(b2,&s->b_pred); Ladd(b,&s->b_pred);
|
|
|
|
cp_loops(b,b1);
|
|
|
|
b->b_idom = common_dom(b1,b2);
|
|
|
|
b->b_flags = b1->b_flags;
|
|
|
|
b->b_next = b1->b_next;
|
|
|
|
b1->b_next = b;
|
|
|
|
|
|
|
|
/* Now adjust the EM text */
|
|
|
|
l = PREV(l1);
|
1991-03-01 14:54:43 +00:00
|
|
|
while (l && INSTR(l) == op_lab) {
|
|
|
|
l1 = l;
|
|
|
|
l = PREV(l);
|
|
|
|
}
|
1984-11-26 15:04:22 +00:00
|
|
|
if (l == (line_p) 0) {
|
|
|
|
b1->b_start = (line_p) 0;
|
|
|
|
} else {
|
|
|
|
l->l_next = (line_p) 0;
|
|
|
|
}
|
1991-03-01 14:54:43 +00:00
|
|
|
if (INSTR(l1) == op_lab) {
|
|
|
|
l = l1;
|
|
|
|
}
|
|
|
|
else {
|
|
|
|
l = newline(OPINSTRLAB);
|
|
|
|
l->l_instr = op_lab;
|
|
|
|
INSTRLAB(l) = freshlabel();
|
|
|
|
DLINK(l,l1);
|
|
|
|
}
|
1984-11-26 15:04:22 +00:00
|
|
|
b->b_start = l;
|
1991-10-25 14:27:59 +00:00
|
|
|
for (l = l2; INSTR(l) != op_bra;) {
|
|
|
|
line_p next = l->l_next;
|
|
|
|
|
1984-11-26 15:04:22 +00:00
|
|
|
assert (l != (line_p) 0);
|
|
|
|
rm_line(l,b2);
|
1991-10-25 14:27:59 +00:00
|
|
|
l = next;
|
1984-11-26 15:04:22 +00:00
|
|
|
}
|
|
|
|
INSTRLAB(l) = INSTRLAB(b->b_start);
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
STATIC bool try_tail(b1,b2)
|
|
|
|
bblock_p b1,b2;
|
|
|
|
{
|
|
|
|
/* See if b1 and b2 end on the same sequence of instructions */
|
|
|
|
|
|
|
|
line_p l1,l2;
|
|
|
|
bblock_p b = (bblock_p) 0;
|
|
|
|
int cnt = 0;
|
|
|
|
/* printf("try block %d and %d\n",b1->b_id,b2->b_id); */
|
|
|
|
|
|
|
|
if (b1->b_start == (line_p) 0 || b2->b_start == (line_p) 0) return FALSE;
|
|
|
|
l1 = last_mnem(b1);
|
|
|
|
l2 = last_mnem(b2);
|
1985-01-23 16:13:57 +00:00
|
|
|
if (l1 == (line_p) 0 || l2 == (line_p) 0) return FALSE;
|
1984-11-26 15:04:22 +00:00
|
|
|
/* printf("consider:\n"); showinstr(l1); showinstr(l2); */
|
|
|
|
if (INSTR(l1) == op_bra) {
|
|
|
|
b = b1;
|
|
|
|
l1 = PREV(l1);
|
|
|
|
}
|
|
|
|
if (INSTR(l2) == op_bra) {
|
|
|
|
b = b2;
|
|
|
|
l2 = PREV(l2);
|
|
|
|
}
|
|
|
|
assert(b != (bblock_p) 0);
|
|
|
|
while(same_instr(l1,l2)) {
|
|
|
|
cnt++;
|
|
|
|
l1 = PREV(l1);
|
|
|
|
l2 = PREV(l2);
|
|
|
|
/* printf("consider:\n"); showinstr(l1); showinstr(l2); */
|
|
|
|
}
|
|
|
|
if (cnt >= 1) {
|
|
|
|
l1 = (l1 == 0 ? b1->b_start : l1->l_next);
|
|
|
|
l2 = (l2 == 0 ? b2->b_start : l2->l_next);
|
|
|
|
if (is_desirable(l1)) {
|
|
|
|
if (b == b1) {
|
|
|
|
jump_cross(l2,l1,b2,b1);
|
|
|
|
Scj++;
|
|
|
|
} else {
|
|
|
|
jump_cross(l1,l2,b1,b2);
|
|
|
|
Scj++;
|
|
|
|
}
|
|
|
|
return TRUE;
|
|
|
|
}
|
|
|
|
}
|
|
|
|
return FALSE;
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
STATIC bool try_pred(b)
|
|
|
|
bblock_p b;
|
|
|
|
{
|
|
|
|
/* See if there is any pair (b1,b2), both in PRED(b) for
|
|
|
|
* which we can perform cross jumping.
|
|
|
|
*/
|
|
|
|
|
|
|
|
register bblock_p b1,b2;
|
|
|
|
register Lindex i,j;
|
|
|
|
lset s = b->b_pred;
|
|
|
|
|
|
|
|
for (i = Lfirst(s); i != (Lindex) 0; i = Lnext(i,s)) {
|
|
|
|
b1 = (bblock_p) Lelem(i);
|
|
|
|
if (Lnrelems(b1->b_succ) != 1) continue;
|
|
|
|
for (j = Lfirst(s); j != (Lindex) 0; j = Lnext(j,s)) {
|
|
|
|
b2 = (bblock_p) Lelem(j);
|
|
|
|
if (b1 != b2 && Lnrelems(b2->b_succ) == 1) {
|
|
|
|
if (try_tail(b1,b2)) return TRUE;
|
|
|
|
}
|
|
|
|
}
|
|
|
|
}
|
|
|
|
return FALSE;
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
cj_optimize(p)
|
|
|
|
proc_p p;
|
|
|
|
{
|
|
|
|
/* Perform cross jumping for procedure p.
|
|
|
|
* In case cases a cross-jumping optimization which give
|
|
|
|
* new opportunities for further cross-jumping optimizations.
|
|
|
|
* Hence we repeat the whole process for the entire procedure,
|
|
|
|
* untill we find no further optimizations.
|
|
|
|
*/
|
|
|
|
|
|
|
|
bblock_p b;
|
|
|
|
bool changes = TRUE;
|
|
|
|
|
1987-10-02 12:52:29 +00:00
|
|
|
if (IS_ENTERED_WITH_GTO(p)) return;
|
1984-11-26 15:04:22 +00:00
|
|
|
while(changes) {
|
|
|
|
changes = FALSE;
|
|
|
|
b = p->p_start;
|
|
|
|
while (b != (bblock_p) 0) {
|
|
|
|
if (try_pred(b)) {
|
|
|
|
changes = TRUE;
|
|
|
|
} else {
|
|
|
|
b = b->b_next;
|
|
|
|
}
|
|
|
|
}
|
|
|
|
}
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
main(argc,argv)
|
|
|
|
int argc;
|
|
|
|
char *argv[];
|
|
|
|
{
|
|
|
|
go(argc,argv,no_action,cj_optimize,no_action,no_action);
|
|
|
|
report("cross jumps",Scj);
|
|
|
|
exit(0);
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
/******
|
|
|
|
* Debugging stuff
|
|
|
|
*/
|
|
|
|
|
|
|
|
extern char em_mnem[]; /* The mnemonics of the EM instructions. */
|
|
|
|
|
|
|
|
STATIC showinstr(lnp) line_p lnp; {
|
|
|
|
|
|
|
|
/* Makes the instruction in `lnp' human readable. Only lines that
|
|
|
|
* can occur in expressions that are going to be eliminated are
|
|
|
|
* properly handled.
|
|
|
|
*/
|
|
|
|
if (lnp == 0) return;
|
|
|
|
if (INSTR(lnp) < sp_fmnem || INSTR(lnp) > sp_lmnem) {
|
|
|
|
printf("\t*** ?\n");
|
|
|
|
return;
|
|
|
|
}
|
|
|
|
|
|
|
|
printf("\t%s", &em_mnem[4 * (INSTR(lnp)-sp_fmnem)]);
|
|
|
|
switch (TYPE(lnp)) {
|
|
|
|
case OPNO:
|
|
|
|
break;
|
|
|
|
case OPSHORT:
|
|
|
|
printf(" %d", SHORT(lnp)); break;
|
|
|
|
case OPOBJECT:
|
|
|
|
printf(" %d", OBJ(lnp)->o_id); break;
|
|
|
|
case OPOFFSET:
|
1987-02-09 17:31:25 +00:00
|
|
|
printf(" %ld", OFFSET(lnp)); break;
|
1984-11-26 15:04:22 +00:00
|
|
|
default:
|
|
|
|
printf(" ?"); break;
|
|
|
|
}
|
|
|
|
printf("\n");
|
|
|
|
} /* showinstr */
|