d0p1/ack
1
0
Fork 0
Code Issues Pull requests Packages Projects Releases Wiki Activity

The register allocator is really a pass, so arrange the code like one.

Browse source
This commit is contained in:
David Given 2016-10-05 23:55:38 +02:00
parent 87e004e4a9
commit d20b63dc94
3 changed files with 6 additions and 6 deletions
Show stats Download patch file Download diff file Expand all files Collapse all files

3
mach/proto/mcg/mcg.h
View file

@ -107,11 +107,10 @@ extern void pass_eliminate_trivial_blocks(struct procedure* proc);
extern void pass_group_irs(struct procedure* proc);
extern void pass_instruction_selector(struct procedure* proc);
extern void pass_promote_float_ops(struct procedure* proc);
extern void pass_register_allocator(struct procedure* proc);
extern void pass_remove_dead_blocks(struct procedure* proc);
extern void pass_split_critical_edges(struct procedure* proc);
extern void register_allocator(struct procedure* proc);
#endif
/* vim: set sw=4 ts=4 expandtab : */

2
mach/proto/mcg/registerallocator.c → mach/proto/mcg/pass_registerallocator.c
View file

@ -20,7 +20,7 @@ static void recursively_walk_dominance_graph(struct basicblock* bb)
}
}
void register_allocator(struct procedure* proc)
void pass_register_allocator(struct procedure* proc)
{
calculate_dominance_graph(proc);

7
mach/proto/mcg/procedure.c
View file

@ -49,7 +49,9 @@ void procedure_compile(struct procedure* proc)
pass_remove_dead_blocks(proc);
procedure_update_bb_graph(proc);
/* Passes from here on can't alter the BB graph */
/* Passes from here on can't alter the BB graph without also updating prevs
* and nexts. */
print_blocks('2', proc);
pass_convert_stack_ops(proc);
@ -62,8 +64,7 @@ void procedure_compile(struct procedure* proc)
print_blocks('6', proc);
pass_instruction_selector(proc);
register_allocator(proc);
pass_register_allocator(proc);
}
static bool collect_outputs_cb(struct ir* ir, void* user)