struct repl {
	struct	repl *next;
	struct	idf *r_idf;		/* name of the macro */
	struct	args *r_args;		/* replacement parameters */
	int	r_level;		/* level of insertion */
	char	*r_ptr;			/* replacement text pointer */
	char	r_text[LAPBUF];		/* replacement text */
};

/* ALLOCDEF "repl" 4 */

#define NO_REPL		(struct repl *)0

/*	The implementation of the ## operator is currently very clumsy.
	When the the ## operator is used the arguments are taken from
	the raw buffer; this buffer contains a precise copy of the
	original argument. The fully expanded copy is in the arg buffer.
	The two copies are here explicitely because:

		#define ABC	f()
		#define	ABCD	2
		#define	g(x, y)	x ## y + h(x)

		g(ABC, D);

	In this case we need two copies: one raw copy for the pasting
	operator, and an expanded one as argument for h().
*/
struct args {
	char	*a_expptr;		/* expanded argument pointer */
	char	*a_expvec[NPARAMS];	/* expanded argument vector */
	char	a_expbuf[ARGBUF];	/* expanded argument buffer space */
	char	*a_rawptr;		/* raw argument pointer */
	char	*a_rawvec[NPARAMS];	/* raw argument vector */
	char	a_rawbuf[ARGBUF];	/* raw argument buffer space */
};

/* ALLOCDEF "args" 2 */

#define NO_ARGS		(struct args *)0