352 lines
7.3 KiB
Plaintext
352 lines
7.3 KiB
Plaintext
/*
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* (c) copyright 1987 by the Vrije Universiteit, Amsterdam, The Netherlands.
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* See the copyright notice in the ACK home directory, in the file "Copyright".
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*/
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/* $Id$ */
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/* EXPRESSION SYNTAX PARSER */
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{
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#include <alloc.h>
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#include "lint.h"
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#include "debug.h"
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#include <flt_arith.h>
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#include "arith.h"
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#include "LLlex.h"
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#include "type.h"
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#include "idf.h"
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#include "label.h"
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#include "expr.h"
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#include "code.h"
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#include "sizes.h"
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extern struct expr *intexpr();
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int InSizeof = 0; /* inside a sizeof- expression */
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int ResultKnown = 0; /* result of the expression is already known */
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/* Since the grammar in the standard is not LL(n), it is modified so that
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* it accepts basically the same grammar. This means that there is no 1-1
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* mapping from the grammar in the standard to the grammar given here.
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* Such is life.
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*/
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}
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/* 3.3.1 */
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primary(register struct expr **expp;) :
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IDENTIFIER
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{dot2expr(expp);}
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constant(expp)
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string(expp)
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'(' expression(expp) ')'
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{ (*expp)->ex_flags |= EX_PARENS; }
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;
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/* Character string literals that are adjacent tokens
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* are concatenated into a single character string
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* literal.
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*/
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string(register struct expr **expp;)
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{ register int i, len;
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register char *str;
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register int fund;
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}
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:
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STRING
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{ str = dot.tk_bts;
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len = dot.tk_len;
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fund = dot.tk_fund;
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}
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[
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STRING
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{ /* A pasted string keeps the type of the first
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* string literal.
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* The pasting of normal strings and wide
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* character strings are stated as having an
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* undefined behaviour.
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*/
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if (dot.tk_fund != fund)
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warning("illegal pasting of string literals");
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str = Realloc(str, (unsigned) (--len + dot.tk_len));
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for (i = 0; i < dot.tk_len; i++)
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str[len++] = dot.tk_bts[i];
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}
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]*
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{ string2expr(expp, str, len); }
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;
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/* 3.3.2 */
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postfix_expression(register struct expr **expp;)
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{ int oper;
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struct expr *e1 = 0;
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struct idf *idf;
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}
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:
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primary(expp)
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[
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'[' expression(&e1) ']'
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{ ch3bin(expp, '[', e1); e1 = 0; }
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'(' parameter_list(&e1)? ')'
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{ ch3bin(expp, '(', e1); call_proto(expp); e1 = 0; }
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[ '.' | ARROW ] { oper = DOT; }
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identifier(&idf) { ch3sel(expp, oper, idf); }
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[
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PLUSPLUS { oper = POSTINCR; }
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MINMIN { oper = POSTDECR; }
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]
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{ ch3incr(expp, oper); }
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]*
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;
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parameter_list(struct expr **expp;)
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{struct expr *e1 = 0;}
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:
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assignment_expression(expp)
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{any2opnd(expp, PARCOMMA);}
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[ %persistent
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','
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assignment_expression(&e1)
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{any2opnd(&e1, PARCOMMA);}
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{ch3bin(expp, PARCOMMA, e1);}
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]*
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;
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%first first_of_type_specifier, type_specifier;
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/* 3.3.3 & 3.3.4 */
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unary(register struct expr **expp;)
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{struct type *tp; int oper;}
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:
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%if (first_of_type_specifier(AHEAD) && AHEAD != IDENTIFIER)
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cast(&tp) unary(expp)
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{ ch3cast(expp, CAST, tp);
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(*expp)->ex_flags |= EX_CAST;
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if (int_size != pointer_size)
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(*expp)->ex_flags &= ~EX_PTRDIFF;
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}
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postfix_expression(expp)
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unop(&oper) unary(expp)
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{ch3mon(oper, expp);}
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size_of(expp)
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;
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/* When an identifier is used in a sizeof()-expression, we must stil not
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* mark it as used.
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* extern int i; .... sizeof(i) .... need not have a definition for i
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*/
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size_of(register struct expr **expp;)
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{struct type *tp;}
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:
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SIZEOF { InSizeof++; } /* handle (sizeof(sizeof(int))) too */
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[%if (first_of_type_specifier(AHEAD) && AHEAD != IDENTIFIER)
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cast(&tp)
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{
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*expp = intexpr(size_of_type(tp, "type"), UNSIGNED);
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(*expp)->ex_flags |= EX_SIZEOF;
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}
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unary(expp)
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{ch3mon(SIZEOF, expp);}
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]
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{ InSizeof--; }
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;
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/* 3.3.5-3.3.17 */
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/* The set of operators in C is stratified in 15 levels, with level
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N being treated in RM 7.N (although this is not the standard
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anymore). The standard describes this in phrase-structure-grammar,
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which we are unable to parse. The description that follows comes
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from the old C-compiler.
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In principle each operator is assigned a rank, ranging
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from 1 to 15. Such an expression can be parsed by a construct
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like:
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binary_expression(int maxrank;)
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{int oper;}
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:
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binary_expression(maxrank - 1)
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[%if (rank_of(DOT) <= maxrank)
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binop(&oper)
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binary_expression(rank_of(oper)-1)
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]?
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;
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except that some call of 'unary' is necessary, depending on the
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grammar.
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This simple view is marred by three complications:
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1. Level 15 (comma operator) is not allowed in many
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contexts and is different.
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2. Level 13 (conditional operator) is a ternary operator,
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which does not fit this scheme at all.
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3. Level 14 (assignment operators) group right-to-left, as
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opposed to 2-12, which group left-to-right (or are
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immaterial).
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4. The operators in level 14 start with operators in levels
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2-13 (RM 7.14: The two parts of a compound assignment
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operator are separate tokens.) This causes LL1 problems.
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This forces us to have four rules:
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binary_expression for level 2-12
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conditional_expression for level 13
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assignment_expression for level 14 and
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expression for the most general expression
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*/
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binary_expression(int maxrank; struct expr **expp;)
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{int oper, OldResultKnown; struct expr *e1;}
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:
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unary(expp)
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[%while (rank_of(DOT) <= maxrank )
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/* '?', '=', and ',' are no binops
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*/
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binop(&oper)
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{ OldResultKnown = ResultKnown;
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if (oper == OR || oper == AND) {
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if (is_cp_cst(*expp) || is_fp_cst(*expp)) {
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if (is_zero_cst(*expp)) {
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if (oper == AND) ResultKnown++;
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} else if (oper == OR) ResultKnown++;
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}
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}
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}
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binary_expression(rank_of(oper)-1, &e1)
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{
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ch3bin(expp, oper, e1);
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ResultKnown = OldResultKnown;
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}
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]*
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;
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/* 3.3.15 */
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conditional_expression(struct expr **expp;)
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{struct expr *e1 = 0, *e2 = 0; int OldResultKnown, ConstExpr=0;}
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:
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/* allow all binary operators */
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binary_expression(rank_of('?') - 1, expp)
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[ '?'
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{ OldResultKnown = ResultKnown;
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if (is_cp_cst(*expp) || is_fp_cst(*expp)) {
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ConstExpr++;
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if (is_zero_cst(*expp)) ResultKnown++;
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}
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}
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expression(&e1)
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':'
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{ if (ConstExpr) {
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if (OldResultKnown == ResultKnown) ResultKnown++;
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else ResultKnown = OldResultKnown;
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}
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}
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conditional_expression(&e2)
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{
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ResultKnown = OldResultKnown;
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ch3bin(&e1, ':', e2);
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opnd2test(expp, '?');
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ch3bin(expp, '?', e1);
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}
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]?
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;
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/* 3.3.16 */
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assignment_expression(struct expr **expp;)
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{ int oper;
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struct expr *e1 = 0;
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}
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:
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conditional_expression(expp)
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[
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asgnop(&oper)
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assignment_expression(&e1)
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{ch3asgn(expp, oper, e1);}
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empty /* LLgen artefact ??? */
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]
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;
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/* 3.3.17 */
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expression(struct expr **expp;)
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{struct expr *e1;}
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:
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assignment_expression(expp)
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[ ','
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assignment_expression(&e1)
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{
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ch3bin(expp, ',', e1);
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}
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]*
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;
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unop(int *oper;) :
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['*' | '&' | '-' | '+' | '!' | '~' | PLUSPLUS | MINMIN]
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{ if (DOT == '&') DOT = ADDRESSOF;
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*oper = DOT;
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}
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;
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multop:
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'*' | '/' | '%'
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;
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addop:
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'+' | '-'
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;
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shiftop:
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LEFT | RIGHT
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;
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relop:
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'<' | '>' | LESSEQ | GREATEREQ
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;
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eqop:
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EQUAL | NOTEQUAL
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;
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arithop:
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multop | addop | shiftop
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'&' | '^' | '|'
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;
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binop(int *oper;) :
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[ arithop | relop | eqop | AND | OR ]
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{*oper = DOT;}
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;
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asgnop(register int *oper;):
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[ '=' | PLUSAB | MINAB | TIMESAB | DIVAB | MODAB
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| LEFTAB | RIGHTAB | ANDAB | XORAB | ORAB ]
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{ *oper = DOT; }
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;
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constant(struct expr **expp;) :
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[
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INTEGER
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FLOATING
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] {dot2expr(expp);}
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;
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/* 3.4 */
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constant_expression (struct expr **expp;) :
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conditional_expression(expp)
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{ chk_cst_expr(expp); }
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;
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identifier(struct idf **idfp;) :
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[ IDENTIFIER
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| TYPE_IDENTIFIER
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]
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{ *idfp = dot.tk_idf; }
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;
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