384 lines
14 KiB
Plaintext
384 lines
14 KiB
Plaintext
.NH 2
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The register allocation phase
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.PP
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.NH 3
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Overview
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.PP
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The RA phase deals with one procedure at a time.
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For every procedure, it first determines which entities
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may be put in a register. Such an entity
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is called an \fIitem\fR.
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For every item it decides during which parts of the procedure it
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might be assigned a register.
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Such a region is called a \fItimespan\fR.
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For any item, several (possibly overlapping) timespans may
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be considered.
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A pair (item,timespan) is called an \fIallocation\fR.
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If the items of two allocations are both live at some
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point of time in the intersections of their timespans,
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these allocations are said to be \fIrivals\fR of each other,
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as they cannot be assigned the same register.
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The rivals-set of every allocation is computed.
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Next, the gains of assigning a register to an allocation are estimated,
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for every allocation.
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With all this information, decisions are made which allocations
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to store in which registers (\fIpacking\fR).
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Finally, the EM text is transformed to reflect these decisions.
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.NH 3
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The item recognition subphase
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.PP
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RA tries to put the following entities in a register:
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.IP -
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a local variable for which a register message was found
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.IP -
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the address of a local variable for which no
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register message was found
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.IP -
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the address of a global variable
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.IP -
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the address of a procedure
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.IP -
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a numeric constant.
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.LP
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Only the \fIaddress\fR of a global variable
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may be put in a register, not the variable itself.
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This approach avoids the very complex problems that would be
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caused by procedure calls and indirect pointer references (see
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.[~[
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aho design compiler
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.] sections 14.7 and 14.8]
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and
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.[~[
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spillman side-effects
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.]]).
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Still, on most machines accessing a global variable using indirect
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addressing through a register is much cheaper than
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accessing it via its address.
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Similarly, if the address of a procedure is put in a register, the
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procedure can be called via an indirect call.
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.PP
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With every item we associate a register type.
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This type is
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.DS
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for local variables: the type contained in the register message
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for addresses of variables and procedures: the pointer type
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for constants: the general type
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.DE
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An entity other than a local variable is not taken to be an item
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if it is used only once within the current procedure.
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.PP
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An item is said to be \fIlive\fR at some point of the program text
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if its value may be used before it is changed.
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As addresses and constants are never changed, all items but local
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variables are always live.
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The region of text during which a local variable is live is
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determined via the live/dead messages generated by the
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Live Variable analysis phase of the Global Optimizer.
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.NH 3
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The allocation determination subphase
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.PP
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If a procedure has more items than registers,
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it may be advantageous to put an item in a register
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only during those parts of the procedure where it is most
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heavily used.
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Such a part will be called a timespan.
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With every item we may associate a set of timespans.
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If two timespans of an item overlap,
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at most one of them may be granted a register,
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as there is no use in putting the same item in two
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registers simultaneously.
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If two timespans of an item are distinct,
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both may be chosen;
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the item will possibly be put in two
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different registers during different parts of the procedure.
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The timespan may also consist
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of the whole procedure.
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.PP
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A list of (item,timespan) pairs (allocations)
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is build, which will be the input to the decision making
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subphase of RA (packing subphase).
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This allocation list is the main data structure of RA.
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The description of the remainder of RA will be in terms
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of allocations rather than items.
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The phrase "to assign a register to an allocation" means "to assign
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a register to the item of the allocation for the duration of
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the timespan of the allocation".
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Subsequent subphases will add more information
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to this list.
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.PP
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Several factors must be taken into account when a
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timespan for an item is constructed:
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.IP 1.
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At any \fIentry point\fR of the timespan where the
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item is live,
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the register must be initialized with the item
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.IP 2.
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At any exit point of the timespan where the item is live,
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the item must be updated.
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.LP
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In order to decrease these costs, we will only consider timespans with
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one entry point
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and no live exit points.
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.NH 3
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The rivals computation subphase
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.PP
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As stated before, several different items may be put in the
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same register, provided they are not live simultaneously.
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For every allocation we determine the intersection
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of its timespan and the lifetime of its item (i.e. the part of the
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procedure during which the item is live).
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The allocation is said to be busy during this intersection.
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If two allocations are ever busy simultaneously they are
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said to be rivals of each other.
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The rivals information is added to the allocation list.
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.NH 3
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The profits computation subphase
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.PP
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To make good decisions, the packing subphase needs to
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know which allocations can be assigned the same register
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(rivals information) and how much is gained by
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granting an allocation a register.
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.PP
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Besides the gains of using a register instead of an
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item,
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two kinds of overhead costs must be
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taken into account:
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.IP -
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the register must be initialized with the item
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.IP -
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the register must be saved at procedure entry
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and restored at procedure exit.
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.LP
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The latter costs should not be due to a single
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allocation, as several allocations can be assigned the same register.
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These costs are dealt with after packing has been done.
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They do not influence the decisions of the packing algorithm,
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they may only undo them.
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.PP
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The actual profits consist of improvements
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of execution time and code size.
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As the former is far more difficult to estimate , we will
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discuss code size improvements first.
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.PP
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The gains of putting a certain item in a register
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depends on how the item is used.
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Suppose the item is
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a pointer variable.
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On machines that do not have a
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double-indirect addressing mode,
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two instructions are needed to dereference the variable
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if it is not in a register, but only one if it is put in a register.
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If the variable is not dereferenced, but simply copied, one instruction
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may be sufficient in both cases.
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So the gains of putting a pointer variable in a register are higher
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if the variable is dereferenced often.
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.PP
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To make accurate estimates, detailed knowledge of
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the target machine and of the code generator
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would be needed.
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Therefore, a simplification has been made that substantially limits
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the amount of target machine information that is needed.
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The estimation of the number of bytes saved does
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not take into account how an item is used.
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Rather, an average number is used.
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So these gains are computed as follows:
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.DS
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#bytes_saved = #occurrences * gains_per_occurrence
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.DE
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The number of occurrences is derived from
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the EM code.
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Note that this is not exact either,
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as there is no one-to-one correspondence between occurrences in
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the EM code and in the assembler code.
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.PP
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The gains of one occurrence depend on:
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.IP 1.
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the type of the item
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.IP 2.
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the size of the item
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.IP 3.
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the type of the register
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.LP
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and for local variables and addresses of local variables:
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.IP 4.
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the type of the local variable
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.IP 5.
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the offset of the variable in the stackframe
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.LP
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For every allocation we try two types of registers: the register type
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of the item and the general register type.
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Only the type with the highest profits will subsequently be used.
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This type is added to the allocation information.
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.PP
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To compute the gains, RA uses a machine-dependent table
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that is read from a machine descriptor file.
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By means of this table the number of bytes saved can be computed
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as a function of the five properties.
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.PP
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The costs of initializing a register with an item
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is determined in a similar way.
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The cost of one initialization is also
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obtained from the descriptor file.
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Note that there can be at most one initialization for any
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allocation.
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.PP
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To summarize, the number of bytes a certain allocation would
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save is computed as follows:
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.DS
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net_bytes_saved = bytes_saved - init_cost
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bytes_saved = #occurrences * gains_per_occ
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init_cost = #initializations * costs_per_init
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.DE
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.PP
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It is inherently more difficult to estimate the execution
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time saved by putting an item in a register,
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because it is impossible to predict how
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many times an item will be used dynamically.
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If an occurrence is part of a loop,
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it may be executed many times.
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If it is part of a conditional statement,
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it may never be executed at all.
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In the latter case, the speed of the program may even get
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worse if an initialization is needed.
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As a clear example, consider the piece of "C" code in Fig. 13.1.
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.DS
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switch(expr) {
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case 1: p(); break;
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case 2: p(); p(); break;
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case 3: p(); break;
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default: break;
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}
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Fig. 13.1 A "C" switch statement
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.DE
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Lots of bytes may be saved by putting the address of procedure p
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in a register, as p is called four times (statically).
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Dynamically, p will be called zero, one or two times,
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depending on the value of the expression.
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.PP
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The optimizer uses the following strategy for optimizing
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execution time:
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.IP 1.
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try to put items in registers during \fIloops\fR first
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.IP 2.
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always keep the initializing code outside the loop
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.IP 3.
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if an item is not used in a loop, do not put it in a register if
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the initialization costs may be higher than the gains
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.LP
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The latter condition can be checked by determining the
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minimal number of usages (dynamically) of the item during the procedure,
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via a shortest path algorithm.
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In the example above, this minimal number is zero, so the address of
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p is not put in a register.
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.PP
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The costs of one occurrence is estimated as described above for the
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code size.
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The number of dynamic occurrences is guessed by looking at the
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loop nesting level of every occurrence.
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If the item is never used in a loop,
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the minimal number of occurrences is used.
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From these facts, the execution time improvement is assessed
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for every allocation.
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.NH 3
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The packing subphase
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.PP
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The packing subphase takes as input the allocation
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list and outputs a
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description of which allocations should be put
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in which registers.
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So it is essentially the decision making part of RA.
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.PP
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The packing system tries to assign a register to allocations one
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at a time, in some yet to be defined order.
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For every allocation A, it first checks if there is a register
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(of the right type)
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that is already assigned to one or more allocations,
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none of which are rivals of A.
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In this case A is assigned the same register.
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Else, A is assigned a new register, if one exists.
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A table containing the number of free registers for every type
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is maintained.
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It is initialized with the number of non-scratch registers of
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the target computer and updated whenever a
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new register is handed out.
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The packing algorithm stops when no more allocations can
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or need be assigned a register.
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.PP
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After an allocation A has been packed,
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all allocations with non-disjunct timespans (including
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A itself) are removed from the allocation list.
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.PP
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In case the number of items exceeds the number of registers, it
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is important to choose the most profitable allocations.
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Due to the possibility of having several allocations
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occupying the same register,
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this problem is quite complex.
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Our packing algorithm uses simple heuristic rules
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and avoids any combinatorial search.
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It has distinct rules for different costs measures.
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.PP
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If object code size is the most important factor,
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the algorithm is greedy and chooses allocations in
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decreasing order of their profits attribute.
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It does not take into account the fact that
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other allocations may be passed over because of
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this decision.
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.PP
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If execution time is at prime stake, the algorithm
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first considers allocations whose timespans consist of loops.
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After all these have been packed, it considers the remaining
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allocations.
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Within the two subclasses, it considers allocations
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with the highest profits first.
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When assigning a register to an allocation with a loop
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as timespan, the algorithm checks if the item has
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already been put in a register during another loop.
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If so, it tries to use the same register for the
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new allocation.
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After all packing has been done,
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it checks if the item has always been assigned the same
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register (although not necessarily during all loops).
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If so, it tries to put the item in that register during
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the entire procedure. This is possible
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if the allocation (item,whole_procedure) is not a rival
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of any allocation with a different item that has been
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assigned to the same register.
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Note that this approach is essentially 'bottom up',
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as registers are first assigned over small regions
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of text which are later collapsed into larger regions.
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The advantage of this approach is the fact that
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the decisions for one loop can be made independently
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of all other loops.
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.PP
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After the entire packing process has been completed,
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we compute for each register how much is gained in using
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this register, by simply adding the net profits
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of all allocations assigned to it.
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This total yield should outweigh the costs of
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saving/restoring the register at procedure entry/exit.
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As most modern processors (e.g. 68000, Vax) have special
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instructions to save/restore several registers,
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the differential costs of saving one extra register are by
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no means constant.
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The costs are read from the machine descriptor file and
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compared to the total yields of the registers.
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As a consequence of this analysis, some allocations
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may have their registers taken away.
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.NH 3
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The transformation subphase
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.PP
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The final subphase of RA transforms the EM text according to the
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decisions made by the packing system.
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It traverses the text of the currently optimized procedure and
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changes all occurrences of items at points where
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they are assigned a register.
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It also clears the score field of the register messages for
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normal local variables and emits register messages with a very
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high score for the pseudo locals.
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At points where registers have to be initialized with items,
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it generates EM code to do so.
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Finally it tries to decrease the size of the stackframe
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of the procedure by looking at which local variables need not
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be given memory locations.
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