ack/lang/cem/cemcom.ansi/expression.g
1989-12-13 12:53:22 +00:00

350 lines
7.2 KiB
Plaintext

/*
* (c) copyright 1987 by the Vrije Universiteit, Amsterdam, The Netherlands.
* See the copyright notice in the ACK home directory, in the file "Copyright".
*/
/* $Header$ */
/* EXPRESSION SYNTAX PARSER */
{
#include <alloc.h>
#include "lint.h"
#include <flt_arith.h>
#include "arith.h"
#include "LLlex.h"
#include "type.h"
#include "idf.h"
#include "label.h"
#include "expr.h"
#include "code.h"
#include "sizes.h"
extern struct expr *intexpr();
int InSizeof = 0; /* inside a sizeof- expression */
int ResultKnown = 0; /* result of the expression is already known */
/* Since the grammar in the standard is not LL(n), it is modified so that
* it accepts basically the same grammar. This means that there is no 1-1
* mapping from the grammar in the standard to the grammar given here.
* Such is life.
*/
}
/* 3.3.1 */
primary(register struct expr **expp;) :
IDENTIFIER
{dot2expr(expp);}
|
constant(expp)
|
string(expp)
|
'(' expression(expp) ')'
{ (*expp)->ex_flags |= EX_PARENS; }
;
/* Character string literals that are adjacent tokens
* are concatenated into a single character string
* literal.
*/
string(register struct expr **expp;)
{ register int i, len;
register char *str;
register int fund;
}
:
STRING
{ str = dot.tk_bts;
len = dot.tk_len;
fund = dot.tk_fund;
}
[
STRING
{ /* A pasted string keeps the type of the first
* string literal.
* The pasting of normal strings and wide
* character strings are stated as having an
* undefined behaviour.
*/
if (dot.tk_fund != fund)
warning("illegal pasting of string literals");
str = Realloc(str, (unsigned) (--len + dot.tk_len));
for (i = 0; i < dot.tk_len; i++)
str[len++] = dot.tk_bts[i];
}
]*
{ string2expr(expp, str, len); }
;
/* 3.3.2 */
postfix_expression(register struct expr **expp;)
{ int oper;
struct expr *e1 = 0;
struct idf *idf;
}
:
primary(expp)
[
'[' expression(&e1) ']'
{ ch3bin(expp, '[', e1); e1 = 0; }
|
'(' parameter_list(&e1)? ')'
{ ch3bin(expp, '(', e1); call_proto(expp); e1 = 0; }
|
[ '.' | ARROW ] { oper = DOT; }
identifier(&idf) { ch3sel(expp, oper, idf); }
|
[
PLUSPLUS { oper = POSTINCR; }
|
MINMIN { oper = POSTDECR; }
]
{ ch3incr(expp, oper); }
]*
;
parameter_list(struct expr **expp;)
{struct expr *e1 = 0;}
:
assignment_expression(expp)
{any2opnd(expp, PARCOMMA);}
[ %persistent
','
assignment_expression(&e1)
{any2opnd(&e1, PARCOMMA);}
{ch3bin(expp, PARCOMMA, e1);}
]*
;
%first first_of_type_specifier, type_specifier;
/* 3.3.3 & 3.3.4 */
unary(register struct expr **expp;)
{struct type *tp; int oper;}
:
%if (first_of_type_specifier(AHEAD) && AHEAD != IDENTIFIER)
cast(&tp) unary(expp)
{ ch3cast(expp, CAST, tp);
(*expp)->ex_flags |= EX_CAST;
}
|
postfix_expression(expp)
|
unop(&oper) unary(expp)
{ch3mon(oper, expp);}
|
size_of(expp)
;
/* When an identifier is used in a sizeof()-expression, we must stil not
* mark it as used.
* extern int i; .... sizeof(i) .... need not have a definition for i
*/
size_of(register struct expr **expp;)
{struct type *tp;}
:
SIZEOF { InSizeof++; } /* handle (sizeof(sizeof(int))) too */
[%if (first_of_type_specifier(AHEAD) && AHEAD != IDENTIFIER)
cast(&tp)
{
*expp = intexpr(size_of_type(tp, "type"),
(int_size == pointer_size ? UNSIGNED : ULONG));
(*expp)->ex_flags |= EX_SIZEOF;
}
|
unary(expp)
{ch3mon(SIZEOF, expp);}
]
{ InSizeof--; }
;
/* 3.3.5-3.3.17 */
/* The set of operators in C is stratified in 15 levels, with level
N being treated in RM 7.N (although this is not the standard
anymore). The standard describes this in phrase-structure-grammar,
which we are unable to parse. The description that follows comes
from the old C-compiler.
In principle each operator is assigned a rank, ranging
from 1 to 15. Such an expression can be parsed by a construct
like:
binary_expression(int maxrank;)
{int oper;}
:
binary_expression(maxrank - 1)
[%if (rank_of(DOT) <= maxrank)
binop(&oper)
binary_expression(rank_of(oper)-1)
]?
;
except that some call of 'unary' is necessary, depending on the
grammar.
This simple view is marred by three complications:
1. Level 15 (comma operator) is not allowed in many
contexts and is different.
2. Level 13 (conditional operator) is a ternary operator,
which does not fit this scheme at all.
3. Level 14 (assignment operators) group right-to-left, as
opposed to 2-12, which group left-to-right (or are
immaterial).
4. The operators in level 14 start with operators in levels
2-13 (RM 7.14: The two parts of a compound assignment
operator are separate tokens.) This causes LL1 problems.
This forces us to have four rules:
binary_expression for level 2-12
conditional_expression for level 13
assignment_expression for level 14 and
expression for the most general expression
*/
binary_expression(int maxrank; struct expr **expp;)
{int oper, OldResultKnown; struct expr *e1;}
:
unary(expp)
[%while (rank_of(DOT) <= maxrank )
/* '?', '=', and ',' are no binops
*/
binop(&oper)
{ OldResultKnown = ResultKnown;
if (oper == OR || oper == AND) {
if (is_cp_cst(*expp) || is_fp_cst(*expp)) {
if (is_zero_cst(*expp)) {
if (oper == AND) ResultKnown++;
} else if (oper == OR) ResultKnown++;
}
}
}
binary_expression(rank_of(oper)-1, &e1)
{
ch3bin(expp, oper, e1);
ResultKnown = OldResultKnown;
}
]*
;
/* 3.3.15 */
conditional_expression(struct expr **expp;)
{struct expr *e1 = 0, *e2 = 0; int OldResultKnown, ConstExpr=0;}
:
/* allow all binary operators */
binary_expression(rank_of('?') - 1, expp)
[ '?'
{ OldResultKnown = ResultKnown;
if (is_cp_cst(*expp) || is_fp_cst(*expp)) {
ConstExpr++;
if (is_zero_cst(*expp)) ResultKnown++;
}
}
expression(&e1)
':'
{ if (ConstExpr) {
if (OldResultKnown == ResultKnown) ResultKnown++;
else ResultKnown = OldResultKnown;
}
}
conditional_expression(&e2)
{
ResultKnown = OldResultKnown;
ch3bin(&e1, ':', e2);
opnd2test(expp, '?');
ch3bin(expp, '?', e1);
}
]?
;
/* 3.3.16 */
assignment_expression(struct expr **expp;)
{ int oper;
struct expr *e1 = 0;
}
:
conditional_expression(expp)
[
asgnop(&oper)
assignment_expression(&e1)
{ch3asgn(expp, oper, e1);}
|
empty /* LLgen artefact ??? */
]
;
/* 3.3.17 */
expression(struct expr **expp;)
{struct expr *e1;}
:
assignment_expression(expp)
[ ','
assignment_expression(&e1)
{
ch3bin(expp, ',', e1);
}
]*
;
unop(int *oper;) :
['*' | '&' | '-' | '+' | '!' | '~' | PLUSPLUS | MINMIN]
{ if (DOT == '&') DOT = ADDRESSOF;
*oper = DOT;
}
;
multop:
'*' | '/' | '%'
;
addop:
'+' | '-'
;
shiftop:
LEFT | RIGHT
;
relop:
'<' | '>' | LESSEQ | GREATEREQ
;
eqop:
EQUAL | NOTEQUAL
;
arithop:
multop | addop | shiftop
|
'&' | '^' | '|'
;
binop(int *oper;) :
[ arithop | relop | eqop | AND | OR ]
{*oper = DOT;}
;
asgnop(register int *oper;):
[ '=' | PLUSAB | MINAB | TIMESAB | DIVAB | MODAB
| LEFTAB | RIGHTAB | ANDAB | XORAB | ORAB ]
{ *oper = DOT; }
;
constant(struct expr **expp;) :
[
INTEGER
|
FLOATING
] {dot2expr(expp);}
;
/* 3.4 */
constant_expression (struct expr **expp;) :
conditional_expression(expp)
{ chk_cst_expr(expp); }
;
identifier(struct idf **idfp;) :
[ IDENTIFIER
| TYPE_IDENTIFIER
]
{ *idfp = dot.tk_idf; }
;