ack/lang/cem/libcc.ansi/stdio/ecvt.c
1989-06-26 10:37:05 +00:00

108 lines
2 KiB
C

/*
* ecvt.c - conversion routines for printing floating point numbers
*/
/* $Header$ */
#ifndef NOFLOAT
static char *cvt(long double value, int ndigit, int *decpt, int *sign, int ecvtflag);
#define NDIGITS 128
char *
ecvt(long double value, int ndigit, int *decpt, int *sign)
{
return cvt(value, ndigit, decpt, sign, 1);
}
char *
fcvt(long double value, int ndigit, int *decpt, int *sign)
{
return cvt(value, ndigit, decpt, sign, 0);
}
static struct powers_of_10 {
long double pval;
long double rpval;
int exp;
} p10[] = {
1.0e32, 1.0e-32, 32,
1.0e16, 1.0e-16, 16,
1.0e8, 1.0e-8, 8,
1.0e4, 1.0e-4, 4,
1.0e2, 1.0e-2, 2,
1.0e1, 1.0e-1, 1,
1.0e0, 1.0e0, 0
};
static char *
cvt(long double value, int ndigit, int *decpt, int *sign, int ecvtflag)
{
static char buf[NDIGITS+1];
register char *p = buf;
register char *pe;
if (ndigit < 0) ndigit = 0;
if (ndigit > NDIGITS) ndigit = NDIGITS;
pe = &buf[ndigit];
buf[0] = '\0';
*sign = 0;
if (value < 0) {
*sign = 1;
value = -value;
}
*decpt = 0;
if (value != 0.0) {
register struct powers_of_10 *pp = &p10[0];
if (value >= 10.0) do {
while (value >= pp->pval) {
value *= pp->rpval;
*decpt += pp->exp;
}
} while ((++pp)->exp > 0);
pp = &p10[0];
if (value < 1.0) do {
while (value * pp->pval < 10.0) {
value *= pp->pval;
*decpt -= pp->exp;
}
} while ((++pp)->exp > 0);
(*decpt)++; /* because now value in [1.0, 10.0) */
}
if (!ecvtflag) {
/* for fcvt() we need ndigit digits behind the dot */
pe += *decpt;
if (pe > &buf[NDIGITS]) pe = &buf[NDIGITS];
}
while (p <= pe) {
*p++ = (int)value + '0';
value = 10.0 * (value - (int)value);
}
if (pe >= buf) {
p = pe;
*p += 5; /* round of at the end */
while (*p > '9') {
*p = '0';
if (p > buf) ++*--p;
else {
*p = '1';
++*decpt;
if (!ecvtflag) {
/* maybe add another digit at the end,
because the point was shifted right
*/
if (pe > buf) *pe = '0';
pe++;
}
}
}
*pe = '\0';
}
return buf;
}
#endif /* NOFLOAT */