146 lines
5.1 KiB
HTML
146 lines
5.1 KiB
HTML
<html>
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<head>
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<title>Lab: file system</title>
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<link rel="stylesheet" href="homework.css" type="text/css" />
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</head>
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<body>
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<h1>Lab: file system</h1>
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<p>In this lab you will add large files and <tt>mmap</tt> to the xv6 file system.
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<h2>Large files</h2>
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<p>In this assignment you'll increase the maximum size of an xv6
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file. Currently xv6 files are limited to 268 blocks, or 268*BSIZE
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bytes (BSIZE is 1024 in xv6). This limit comes from the fact that an
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xv6 inode contains 12 "direct" block numbers and one "singly-indirect"
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block number, which refers to a block that holds up to 256 more block
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numbers, for a total of 12+256=268. You'll change the xv6 file system
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code to support a "doubly-indirect" block in each inode, containing
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256 addresses of singly-indirect blocks, each of which can contain up
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to 256 addresses of data blocks. The result will be that a file will
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be able to consist of up to 256*256+256+11 blocks (11 instead of 12,
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because we will sacrifice one of the direct block numbers for the
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double-indirect block).
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<h3>Preliminaries</h3>
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<p>Modify your Makefile's <tt>CPUS</tt> definition so that it reads:
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<pre>
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CPUS := 1
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</pre>
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<b>XXX doesn't seem to speedup things</b>
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<p>Add
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<pre>
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QEMUEXTRA = -snapshot
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</pre>
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right before
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<tt>QEMUOPTS</tt>
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<p>
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The above two steps speed up qemu tremendously when xv6
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creates large files.
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<p><tt>mkfs</tt> initializes the file system to have fewer
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than 1000 free data blocks, too few to show off the changes
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you'll make. Modify <tt>param.h</tt> to
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set <tt>FSSIZE</tt> to:
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<pre>
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#define FSSIZE 20000 // size of file system in blocks
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</pre>
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<p>Download <a href="big.c">big.c</a> into your xv6 directory,
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add it to the UPROGS list, start up xv6, and run <tt>big</tt>.
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It creates as big a file as xv6 will let
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it, and reports the resulting size. It should say 140 sectors.
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<h3>What to Look At</h3>
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The format of an on-disk inode is defined by <tt>struct dinode</tt>
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in <tt>fs.h</tt>. You're particularly interested in <tt>NDIRECT</tt>,
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<tt>NINDIRECT</tt>, <tt>MAXFILE</tt>, and the <tt>addrs[]</tt> element
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of <tt>struct dinode</tt>. Look Figure 7.3 in the xv6 text for a
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diagram of the standard xv6 inode.
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<p>
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The code that finds a file's data on disk is in <tt>bmap()</tt>
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in <tt>fs.c</tt>. Have a look at it and make sure you understand
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what it's doing. <tt>bmap()</tt> is called both when reading and
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writing a file. When writing, <tt>bmap()</tt> allocates new
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blocks as needed to hold file content, as well as allocating
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an indirect block if needed to hold block addresses.
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<p>
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<tt>bmap()</tt> deals with two kinds of block numbers. The <tt>bn</tt>
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argument is a "logical block" -- a block number relative to the start
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of the file. The block numbers in <tt>ip->addrs[]</tt>, and the
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argument to <tt>bread()</tt>, are disk block numbers.
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You can view <tt>bmap()</tt> as mapping a file's logical
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block numbers into disk block numbers.
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<h3>Your Job</h3>
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Modify <tt>bmap()</tt> so that it implements a doubly-indirect
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block, in addition to direct blocks and a singly-indirect block.
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You'll have to have only 11 direct blocks, rather than 12,
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to make room for your new doubly-indirect block; you're
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not allowed to change the size of an on-disk inode.
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The first 11 elements of <tt>ip->addrs[]</tt> should be
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direct blocks; the 12th should be a singly-indirect block
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(just like the current one); the 13th should be your new
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doubly-indirect block.
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<p>
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You don't have to modify xv6 to handle deletion of files with
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doubly-indirect blocks.
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<p>
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If all goes well, <tt>big</tt> will now report that it
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can write sectors. It will take <tt>big</tt> minutes
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to finish.
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<b>XXX this runs for a while!</b>
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<h3>Hints</h3>
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<p>
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Make sure you understand <tt>bmap()</tt>. Write out a diagram of the
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relationships between <tt>ip->addrs[]</tt>, the indirect block, the
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doubly-indirect block and the singly-indirect blocks it points to, and
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data blocks. Make sure you understand why adding a doubly-indirect
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block increases the maximum file size by 256*256 blocks (really -1),
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since you have to decrease the number of direct blocks by one).
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<p>
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Think about how you'll index the doubly-indirect block, and
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the indirect blocks it points to, with the logical block
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number.
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<p>If you change the definition of <tt>NDIRECT</tt>, you'll
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probably have to change the size of <tt>addrs[]</tt>
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in <tt>struct inode</tt> in <tt>file.h</tt>. Make sure that
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<tt>struct inode</tt> and <tt>struct dinode</tt> have the
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same number of elements in their <tt>addrs[]</tt> arrays.
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<p>If you change the definition of <tt>NDIRECT</tt>, make sure to create a
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new <tt>fs.img</tt>, since <tt>mkfs</tt> uses <tt>NDIRECT</tt> too to build the
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initial file systems. If you delete <tt>fs.img</tt>, <tt>make</tt> on Unix (not
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xv6) will build a new one for you.
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<p>If your file system gets into a bad state, perhaps by crashing,
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delete <tt>fs.img</tt> (do this from Unix, not xv6). <tt>make</tt> will build a
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new clean file system image for you.
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<p>Don't forget to <tt>brelse()</tt> each block that you
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<tt>bread()</tt>.
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<p>You should allocate indirect blocks and doubly-indirect
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blocks only as needed, like the original <tt>bmap()</tt>.
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<h2>Memory-mapped files</h2>
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</body>
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</html>
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