ack/lang/cem/libcc.ansi/math/atan.c

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1989-05-10 16:08:14 +00:00
/*
* (c) copyright 1988 by the Vrije Universiteit, Amsterdam, The Netherlands.
* See the copyright notice in the ACK home directory, in the file "Copyright".
*
* Author: Ceriel J.H. Jacobs
*/
/* $Header$ */
#include <errno.h>
#include <float.h>
#include <math.h>
#include "localmath.h"
double
atan(double x)
{
/* The interval [0, infinity) is treated as follows:
Define partition points Xi
X0 = 0
X1 = tan(pi/16)
X2 = tan(3pi/16)
X3 = tan(5pi/16)
X4 = tan(7pi/16)
X5 = infinity
and evaluation nodes xi
x2 = tan(2pi/16)
x3 = tan(4pi/16)
x4 = tan(6pi/16)
x5 = infinity
An argument x in [Xn-1, Xn] is now reduced to an argument
t in [-X1, X1] by the following formulas:
t = 1/xn - (1/(xn*xn) + 1)/((1/xn) + x)
arctan(x) = arctan(xi) + arctan(t)
For the interval [0, p/16] an approximation is used:
arctan(x) = x * P(x*x)/Q(x*x)
*/
static struct precomputed {
double X; /* partition point */
double arctan; /* arctan of evaluation node */
double one_o_x; /* 1 / xn */
double one_o_xsq_p_1; /* 1 / (xn*xn) + 1 */
} prec[5] = {
{ 0.19891236737965800691159762264467622,
0.0,
0.0, /* these don't matter */
0.0 } ,
{ 0.66817863791929891999775768652308076, /* tan(3pi/16) */
M_PI_8,
2.41421356237309504880168872420969808,
6.82842712474619009760337744841939616 },
{ 1.49660576266548901760113513494247691, /* tan(5pi/16) */
M_PI_4,
1.0,
2.0 },
{ 5.02733949212584810451497507106407238, /* tan(7pi/16) */
M_3PI_8,
0.41421356237309504880168872420969808,
1.17157287525380998659662255158060384 },
{ DBL_MAX,
M_PI_2,
0.0,
1.0 }};
/* Hart & Cheney # 5037 */
static double p[5] = {
0.7698297257888171026986294745e+03,
0.1557282793158363491416585283e+04,
0.1033384651675161628243434662e+04,
0.2485841954911840502660889866e+03,
0.1566564964979791769948970100e+02
};
static double q[6] = {
0.7698297257888171026986294911e+03,
0.1813892701754635858982709369e+04,
0.1484049607102276827437401170e+04,
0.4904645326203706217748848797e+03,
0.5593479839280348664778328000e+02,
0.1000000000000000000000000000e+01
};
int negative = x < 0.0;
register struct precomputed *pr = prec;
if (negative) {
x = -x;
}
while (x > pr->X) pr++;
if (pr != prec) {
x = pr->arctan +
atan(pr->one_o_x - pr->one_o_xsq_p_1/(pr->one_o_x + x));
}
else {
double xsq = x*x;
x = x * POLYNOM4(xsq, p)/POLYNOM5(xsq, q);
}
return negative ? -x : x;
}